9=4.9x^2

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Solution for 9=4.9x^2 equation:



9=4.9x^2
We move all terms to the left:
9-(4.9x^2)=0
We get rid of parentheses
-4.9x^2+9=0
a = -4.9; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-4.9)·9
Δ = 176.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{176.4}}{2*-4.9}=\frac{0-\sqrt{176.4}}{-9.8} =-\frac{\sqrt{}}{-9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{176.4}}{2*-4.9}=\frac{0+\sqrt{176.4}}{-9.8} =\frac{\sqrt{}}{-9.8} $

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